Dividing g by f we have g=f.h+k, where k is of degree at most 1, h,k have rational coefficients. We have g(y)=f(y).h(y)+k(y) and so k(y)=0. But for k with rational coefficients say u,v, the only possible way to u.y+v=0 is u=v=0. So f divides g. After division we obtain g(x)=(x-a).f(x) with the coefficients holding the identities induced by ↑ BakyX:.
Jak se nazývá množina shodných disjunktních krychlí? Ragú